2t^2-9t+2=0

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Solution for 2t^2-9t+2=0 equation: 



2t^2-9t+2=0

a = 2; b = -9; c = +2;
Δ = b2-4ac
Δ = -92-4·2·2
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{65}}{2*2}=\frac{9-\sqrt{65}}{4}
$


$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{65}}{2*2}=\frac{9+\sqrt{65}}{4}
$

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